What is the stiffness coefficient of the tibia if a person weighs 80 kilograms, and the bone is compressed by 0.3 mm?

Given:

m = 80 kilograms – the mass of a person;

g = 10 m / s ^ 2 – acceleration of gravity;

dx = 0.3 millimeters = 0.0003 meters – the amount by which the tibia is compressed.

It is required to determine k (Newton / meter) – the coefficient of stiffness of the tibia.

Let’s find the force of gravity that acts on a person:

F = m * g = 80 * 10 = 800 Newton.

Then the stiffness coefficient will be equal to:

k = F / dx = 800 / 0.0003 = 800 * 10 ^ 4/3 = 8 * 10 ^ 6/3 = 2.7 * 10 ^ 6 Newton / meter.

Answer: the coefficient of stiffness of the tibia is 2.7 * 10 ^ N / m.