What is the stiffness of a spring in a pendulum if its oscillation period is 0.1 s
| October 4, 2021 | education
What is the stiffness of a spring in a pendulum if its oscillation period is 0.1 s, and the mass of the pendulum’s weight is 250 g?
To determine the value of the stiffness of the spring used in the pendulum, we apply the formula: T = 2 * Π * √ (m / k), whence we express: k = m * 4 * Π ^ 2 / T ^ 2.
Variables: m is the mass of the pendulum load (m = 250 g = 0.25 kg); T – oscillation period (T = 0.1 s).
Calculation: k = m * 4 * Π ^ 2 / T ^ 2 = 0.25 * 4 * 3.14 ^ 2 / 0.12 = 985.96 N / m ≈ 986 N / m.
Answer: The spring used in the swingarm has a stiffness of 986 N / m.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
