What is the stiffness of a spring in a pendulum if its oscillation period is 0.1 s, and the mass of the pendulum’s weight is 250 g?
To determine the value of the stiffness of the spring used in the pendulum, we apply the formula: T = 2 * Π * √ (m / k), whence we express: k = m * 4 * Π ^ 2 / T ^ 2.
Variables: m is the mass of the pendulum load (m = 250 g = 0.25 kg); T – oscillation period (T = 0.1 s).
Calculation: k = m * 4 * Π ^ 2 / T ^ 2 = 0.25 * 4 * 3.14 ^ 2 / 0.12 = 985.96 N / m ≈ 986 N / m.
Answer: The spring used in the swingarm has a stiffness of 986 N / m.
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