# What is the stiffness of a spring in a pendulum if its oscillation period is 0.1 s

October 4, 2021 | education

| **What is the stiffness of a spring in a pendulum if its oscillation period is 0.1 s, and the mass of the pendulum’s weight is 250 g?**

To determine the value of the stiffness of the spring used in the pendulum, we apply the formula: T = 2 * Π * √ (m / k), whence we express: k = m * 4 * Π ^ 2 / T ^ 2.

Variables: m is the mass of the pendulum load (m = 250 g = 0.25 kg); T – oscillation period (T = 0.1 s).

Calculation: k = m * 4 * Π ^ 2 / T ^ 2 = 0.25 * 4 * 3.14 ^ 2 / 0.12 = 985.96 N / m ≈ 986 N / m.

Answer: The spring used in the swingarm has a stiffness of 986 N / m.

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