What is the sum of the coefficient in the equation for the combustion of propane in an excess of oxygen?

The reaction equation for the combustion of propane in an excess of oxygen: С3H8 + 5O2 = 3CO2 + 4H2O

If there is an excess of oxygen in the reaction, then the reaction will go to the end, i.e. complete combustion will occur. The reaction products in this case are carbon dioxide and water.

The sum of the odds: 1 + 5 + 3 + 4 = 13.



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