What is the sum of the square of the difference between the cubes of the numbers 3 and 1

What is the sum of the square of the difference between the cubes of the numbers 3 and 1 and the triple cube of their difference?

(3 ^ 3-1 ^ 3) ^ 2 + 3 (3-1) ^ 3 = 26 ^ 2 +24 = 26 ^ 2 + 24 = 676 +24 = 700.
Answer: 700.



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