What is the surface area of a cube with a volume of 64 cm3?

Considering that all edges of a cube are equal, knowing the volume, we find the edge of the cube:

V = a ^ 3 = 64 cm3.

a = 3√‾64 = 3√‾43 = 4 cm.

The area of one face is the product of two edges of the cube:

S = a ^ 2 = 4 ^ 2 = 16 cm2.

In total, the cube has 6 faces, therefore the area of its entire surface will be:

S = 6 * a ^ 2 = 6 * 4 ^ 2 = 6 * 16 = 96 cm2.

Answer: The surface area of a cube with a volume of 64 cm3 is 96 cm2.