What is the surface area of the control panel if it is 4 times the surface area
What is the surface area of the control panel if it is 4 times the surface area of a rectangular screen with a perimeter of 16 dm and a width of 2 dm?
To solve this problem, recall the formula for the area of a rectangle. The area of the rectangle is equal to the product of the length and the width. S = a * b, where a is the length and b is the width. The perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let’s calculate what the length is equal to.
16 = 2 * (a + 2);
a + 2 = 16/2;
a + 2 = 7;
a = 7 – 2;
a = 5.
Let’s calculate what the area is equal to.
S = 5 * 2 = 10 sq. Dm.
Let’s calculate what the area of the control panel is equal to.
S = 4 * 10 = 40 sq. Dm.
Answer: 40 sq. Dm.