What is the temperature of the mixture if you mix 600 g of water at 80 ° and 200 g of water at 20 °?
| June 26, 2021 | education
These tasks: hot water parameters (m1 = 600 g (in SI m1 = 0.6 kg); t1 = 80 ºС); cold water parameters (m2 = 200 g (in SI m2 = 0.2 kg); t2 = 20 ºС).
To determine the temperature of the mixture formed, we use the equality:
Cw * m1 * (t1 – t) = Cw * m2 * (t – t2).
m1 * (t1 – t) = m2 * (t – t2).
0.6 * (80 – t) = 0.2 * (t – 20).
48 – 0.6t = 0.2t – 4.
0.8t = 52 and t = 52 / 0.8 = 65 ºС.
Answer: The resulting mixture should have a temperature of 65 ºС.
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