What is the thickness of the kerosene layer if it has 4 kPa on the bottom of the vessel?

Let’s give the data to us in the SI system:
P = 4 kPa = 4000 Pa.
According to Pascal’s law:
The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:
P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth, g = 9.8 m / s2, h is the thickness of the liquid layer.
Let us express from this formula – the thickness of the liquid layer:
h = P / (ρ * g)
According to the reference book, the density of kerosene is ρ = 800 kg / m³.
substitute the numerical values, we have:
h = P / (ρ * g) = 4000 / (800 * 9.8) = 0.51 m

Answer: depth 0.51 m



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