What is the titer of 0.1150 n NaOH solution? What is the mass of NaOH contained in 500 ml of this solution.

Given:
SN (NaOH) = 0.1150 n
V (NaOH) = 500 ml

Find:
T (NaOH) -?
m (NaOH) -?

Solution:
1) Calculate the titer of sodium hydroxide solution:
T (NaOH) = m (NaOH) / V solution (NaOH);
Cn (NaOH) = z * Cm (NaOH) = z * n (NaOH) / V solution (NaOH);
T (NaOH) = (M (NaOH) * Cn (NaOH)) / (z * 1000) = (40 * 0.1150) / (1 * 1000) = 0.0046 g / ml;
2) Calculate the mass of sodium hydroxide:
m (NaOH) = T (NaOH) * V solution (NaOH) = 0.0046 * 500 = 2.3 g.

Answer: The titer of the NaOH solution is 0.0046 g / ml; weight of NaOH – 2.3 g.