What is the total energy of a 9 g bullet traveling at a speed of 300 m / s at an altitude of 90 cm?

Initial data: m (bullet weight) = 9 g (0.009 kg); V (bullet velocity) = 300 m / s; h (height at which the bullet flies) = 90 cm (0.9 m).

Reference data: g (acceleration due to gravity) ≈ 10 m / s2.

The total energy of the bullet can be determined by the formula: Епол. = Ek + En = 0.5 * m * V ^ 2 + m * g * h.

Calculation: Ecomplete. = 0.5 * 0.009 * 300 ^ 2 + 0.009 * 10 * 0.9 = 405.081 J.

Answer: The total energy of the bullet is 405.081 J.



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