What is the total kinetic energy of translational motion of 2 mol of an ideal gas

What is the total kinetic energy of translational motion of 2 mol of an ideal gas at a temperature of 27 ° C? Universal gas constant 8.31 J / (mol * K)

Data: ν – amount of substance (ν = 2 mol); T – abs. temperature (Т = 300 К (27 ºС)).

Const: R – univers. gas constant (according to the condition taken. R = 8.31 J / (mol * K))).

To find out the required total kinetic energy of 2 mol of taken gas, consider the formula: Ekx = 1.5 * ν * R * T.

Let’s perform the calculation: Ekx = 1.5 * 2 * 8.31 * 300 ≈ 7.5 * 10 ^ 3 J.

Answer: The total kinetic energy, according to the calculation, is 7.5 kJ.