What is the traction force of a tractor if it drives a 600 kg trailer with an acceleration of 0.1 m / s2

| September 9, 2021 | education

What is the traction force of a tractor if it drives a 600 kg trailer with an acceleration of 0.1 m / s2, and the resistance to movement is 2 kN?

m = 600 kg.

a = 0.1 m / s ^ 2.

Fcopr = 2 kN = 2000 N.

Ftyag -?

Two forces act on the trailer in the horizontal direction: in the direction of movement, the traction force of the tractor Ftyag, in the opposite direction of movement, the resistance force Fcopr.

The resultant of the two forces F will be the difference: F = Ftyag – Fcomp.

Let’s write Newton’s 2 law for a trailer: m * a = F, where m is the mass of the trailer, a is the acceleration of the trailer, F is the resultant of all forces that act on the trailer ..

m * a = Ftyag – Fcomp.

Ftyag = m * a + Fcomp.

Ftyag = 600 kg * 0.1 m / s ^ 2 + 2000 N = 2060 N.

Answer: the traction force of the tractor is Ftyag = 2060 N.



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