What is the useful work if the body, when heated, received 250 kJ of energy, and the efficiency is 50%?
| April 11, 2021 | education
Initial data: Q (the amount of energy received by heat during heating) = 250 kJ = 250 * 10 ^ 3 J; η (efficiency) = 50% = 0.5.
The useful work is determined from the formula for calculating the efficiency: η = A / Q, whence A = η * Q.
Let’s perform the calculation: A = 0.5 * 250 * 10 ^ 3 = 125 * 10 ^ 3 J = 125 kJ.
Answer: The useful work is 125 kJ.
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