What is the value of the path traveled by the body if its initial speed on the section is 54 km / h, the final speed is 90 km / h, and the acceleration is 2 m / s?
The distance traveled by the body can be calculated using the formula:
S = (V² – V0²) / 2a, where V is the final speed of the body (V = 90 km / h = 90 / 3.6 m / s = 25 m / s), V0 is the initial speed of the body (V0 = 54 km / h = 54 / 3.6 m / s = 15 m / s), and – acceleration of body movement (a = 2 m / s²).
Let’s calculate the value of the path:
S = (V² – V0²) / 2a = (25² – 15²) / (2 * 2) = (625 – 225) / 4 = 400/4 = 100 m.
Answer: The value of the path traversed by the body is 100 m.
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