What is the voltage at the ends of an aluminum wire 150 cm long, if the cross-sectional area

What is the voltage at the ends of an aluminum wire 150 cm long, if the cross-sectional area is 0.1 mm2, with a current strength of 0.5 A in it?

Data: l (length of the considered aluminum wire) = 150 cm (in SI l = 1.5 m); S (cross-sectional area) = 0.1 mm2; I (current in the wire) = 0.5 A.

Reference values: ρ (electrical resistivity of aluminum at 20 ºС) = 0.028 Ohm * mm2 / m.

The voltage at the ends of the considered aluminum wire is determined by the formula: U = I * R = I * ρ * l / S.

Let’s perform the calculation: U = 0.5 * 0.028 * 1.5 / 0.1 = 0.21 V.

Answer: A voltage of 0.21 V is applied to the ends of the aluminum wire in question.