What is the volume of 10 mol of iron?

Mass m of substance:
m = nM, where n is the number of moles of the substance, M is the molar mass.
Relative atomic mass of iron: 56 amu eat.
Mass of one mole of iron (molar mass M): 56 g = 0.056 kg / mol.
m = 10 mol * 0.056 kg / mol = 0.56 kg.

Volume V:
V = m / r, where r is density.
V = 0.56 kg / 7800 kg / m³ = 0.00007179 m³ = 71.79 cm³

Answer: 7.154 * 10⁻⁵ m³ = 71.79 cm³.