What is the volume of 11 mg of carbon dioxide?

Given:
m (CO2) = 11 mg = 0.011 g

To find:
V (CO2) -?

1) n (CO2) = m / M = 0.011 / 44 = 0.00025 mol;
2) V (CO2) = n * Vm = 0.00025 * 22.4 = 0.0056 l.

Answer: The CO2 volume is 0.0056 liters.



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