What is the volume of 15.36 g of sulfur (IV) oxide? How many gas molecules are there in this mass of sulfur (IV) oxide?

sulfur (IV) oxide is SO2, its molar mass is M (SO2) = M (S) + 2 * M (O) = 32 + 2 * 16 = 64 g / mol
the amount of substance n (SO2) = m (SO2) / M (SO2), where m (SO2) is the mass of SO2
n (SO2) = 15.36 / 64 = 0.24 mol
Under normal conditions, 1 mol of any gas occupies a volume of 22.4 l – Vm = 22.4 l / mol
So V (SO2) = Vm * n (SO2) = 0.24 * 22.4 = 5.376 l
1 mole of a substance contains 6.02 * 10 ^ 23 molecules – this is Avogadro’s number – Na
N is the number of molecules in a given volume N (SO2) = Na * n (SO2) = 6.02 * 10 ^ 23 * 0.24 = 1.4448 * 10 ^ 23 molecules