What is the volume of 3 kmol of gas at a pressure of 1 MPa and a temperature of 100C?

Ideal gas equation of state (Mendeleev – Clapeyron equation):
P * V = n * R * T, where P is the gas pressure (P = 1 MPa = 1 * 10 ^ 6 Pa), V is the gas volume (m ^ 3), n is the amount of substance, concentration (n = 3 kmol = 3000 mol), R is the Boltzmann constant (R = 8.31J / (mol * K)), T is the absolute temperature (T = 100C = 373K).
Let’s express and calculate the gas volume:
V = n * R * T / P = 3000 * 8.31 * 373/10 ^ 6 = 9.3 m ^ 3.
Answer: Gas occupies a volume equal to 9.3 m ^ 3.