What is the volume of 50 moles of lead?

Problem data: ν (the amount of substance contained in the taken lead) = 50 mol.

Constants: M (molar mass of lead) = 0.2072 kg / mol; ρс (lead density) = 11300 kg / m3.

The volume, which is occupied by 50 mol of lead, is determined by the formula: V = m / ρс = ν * M / ρс.

Let’s make a calculation: V = 50 * 0.2072 / 11300 ≈ 9.168 * 10-4 m3 = 916.8 cm3.

Answer: 50 mol of lead occupies a volume of 916.8 cm3.



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