What is the volume of 8.0 g of sulfur oxide?

Given:
m (SO2) = 8.0 g
Vm = 22.4 l / mol

To find:
V (SO2) -?

Decision:
1) Using the periodic system of D.I.Mendeleev, calculate the molar mass of sulfur oxide:
M (SO2) = Mr (SO2) = Ar (S) * N (S) + Ar (O) * N (O) = 32 * 1 + 16 * 2 = 64 g / mol;
2) Calculate the amount of sulfur oxide substance:
n (SO2) = m (SO2) / M (SO2) = 8/64 = 0.125 mol;
3) Calculate the volume of sulfur oxide (under normal conditions):
V (SO2) = n (SO2) * Vm = 0.125 * 22.4 = 2.8 liters.

Answer: The volume of SO2 is 2.8 l