What is the volume of 96% (by weight) sulfuric acid (with a density of 1.84 g / ml)

What is the volume of 96% (by weight) sulfuric acid (with a density of 1.84 g / ml) and how much water should be taken to prepare 100 ml of a 15% (by weight) sulfuric acid solution (with a density of 1.1 g / ml).

Determine the weights of the components of the solution.

To do this, it is necessary to multiply their mass fraction by the weight of the solution.

Let’s calculate the weight of pure sulfuric acid.

M pure acid = 100 x 1.1 x 0.15 = 16.5 grams;

In order to find the volume of a sulfuric acid solution with such an acid weight, it is necessary to divide this acid weight by its concentration and density.

The volume with a solution of sulfuric acid will be:

V sulfuric acid solution = 16.5 / 0.96 / 1.84 = 9.341 ml;

The weight of water to be added will be:

M water = 100 x 1.1 x 0.85 – 16.5 x 0.04 = 93.5 – 0.66 = 92.84 grams;

(We take into account the water in the sulfuric acid solution).

Let’s check:

M solution = M acid + M water = 5 + 45 = 50 grams;