What is the volume of a body if an Archimedean force of 14.5 N acts on it in water?

The buoyant force of Archimedes acts on a body in water, which is equal to:
Fa = ρ * g * V, where Fa is the value of the buoyancy force of Archimedes (Fa = 14.5 N), ρ is the density of fresh water (we take ρ = 1000 kg / m ^ 3), g is the acceleration of gravity (we take g = 10 m / s ^ 2), V is the volume of the submerged part of the body (m ^ 3).
Let’s express and calculate the volume of the body:
V = Fa / (ρ * g) = 14.5 / (1000 * 10) = 0.00145 m ^ 3 = 1.45 * 10 ^ -3 m ^ 3.
Answer: The volume of the body is 1.45 * 10 ^ -3 m ^ 3.