What is the volume of a room, the length of which is 8 m 2 dm, the width is 6 m 5 dm, and the height is 3 m 5 dm?

In order to determine the volume of the room, let’s assume that it has the form of a geometric figure called a rectangular parallelepiped. As you know, with the known three dimensions: the length a and the width b of the base, which is a rectangle, as well as the height h, the volume V of a rectangular parallelepiped can be calculated by the formula V = a * b * h.
The task gives all three dimensions of the room: a = 8 m 2 dm, b = 6 m 5 dm and h = 3 m 5 dm. First, we express all measurements in decimetres, using the equality 1 m = 10 dm. We have: a = 8 m 2 dm = (8 * 10) dm = 2 dm = 82 dm, b = 6 m 5 dm = (6 * 10) dm + 5 dm = 65 dm and h = 3 m 5 dm = ( 3 * 10) dm + 5 dm = 35 dm.
Now we calculate the volume V = (82 dm) * (65 dm) * (35 dm) = (82 * 65 * 35) dm³ = 186550 dm³.
Usually, the volume of a room is expressed in cubic meters. Using the equality 1 m³ = 1000 dm³, we calculate: V = 186550 dm³ = (186550: 1000) m³ = 186.55 m³.
Answer: The volume of the room is 186.55 m³.