What is the volume of aluminum that went into the manufacture of a pot with a mass of 0.5 kg?

Problem data: m (mass of the made pan) = 0.5 kg.

Reference data: according to the condition ρа (aluminum density) = 2700 kg / m3.

The volume of consumed aluminum for the manufacture of the pan is determined by the formula: V = m / ρа.

Let’s make a calculation: V = 0.5 / 2700 = 1.85 * 10-4 m3 = 185 cm3.

Answer: For the manufacture of the pan, 185 cm3 of aluminum was used.



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