What is the volume of an aluminum bar on which an Archimedean force of 120N acts in kerosene?
| February 20, 2021 | education
Initial data: Fа (Archimedes force, which acts on an aluminum bar) = 120 N.
Reference data: ρ (density of kerosene) = 800 kg / m3; g (acceleration due to gravity) = 10 m / s2.
The volume of an aluminum bar can be determined from the formula for calculating the buoyancy force of Archimedes: Fа = ρ * g * V, whence V = Fа / (ρ * g).
Let’s calculate: V = 120 / (800 * 10) = 0.015 m3 = 15 dm3.
Answer: The volume of the aluminum bar is 15 dm3.
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