What is the volume of an aluminum bar, on which an Archimelian force of 120 N acts in kerosene?

To determine the value of the volume of the specified aluminum bar, we apply the following formula (Archimedes’ law): Farh = ρк * g * V, from where we express: V = Faрh / (ρк * g).

Constants and variables: Farh – Archimedes force acting on the specified bar (Fa = 120 N); ρк – density of kerosene (ρк = 800 kg / m3); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: V = Faх / (ρк * g) = 120 / (800 * 10) = 15 * 10 ^ -3 m3 = 15 dm3.

Answer: The volume of the indicated aluminum bar is 15 dm3.