What is the volume of carbon dioxide and how many grams of water are formed when 60 liters of ethane are burned?

The ethane oxidation reaction is described by the following chemical reaction equation.

2C2H6 + 7O2 = 4CO2 + 6H2O;

According to the coefficients of this equation, 7 oxygen molecules are required to oxidize 2 ethane molecules. In this case, 4 molecules of carbon dioxide are synthesized.

Let’s calculate the amount of ethane available.

To do this, we divide the available gas volume by the volume of 1 mole of ideal gas under normal conditions.

N C2H6 = 60 / 22.4 = 2.679 mol;

The amount of carbon dioxide will be.

N CO 2 = N C 2 H 6 x 2 = 2.679 x 2 = 5.358 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V CO2 = 5.358 x 22.4 = 120 liters;