What is the volume of carbon dioxide and the mass of water formed as a result of the combustion of 50 liters of methane.

Given:
V (CH4) = 50 l
To find:
V (CO2) =?
m (H2O) =?
Decision:
1) Let’s compose the equation of the chemical reaction, let the carbon dioxide be x l.
CH4 + 2O2 = CO2 + H2O
2) 50 l: 22.4 l = xl: 22.4 l
x = (50 x 22.4): 22.4 = 50 liters of CO2
2) M (H2O) = 2 + 16 = 18 g / mol, since 2 mol, then 36 g / mol
Let Mr.
50 l: 22.4 l = y: 36
y = (50 x 36): 22.4 = 80.3 g.
Answer: V (CO2) = 50 l.
m (H2O) = 80.3 g.