What is the volume of carbon dioxide formed when calcining a 10 g CaCO3 salt?

Given:
m (CaCO3) = 10 g
To find:
V (CO2) -?
Decision:
1) CaCO3 => CaO + CO2;
2) n (CaCO3) = m (CaCO3) / M (CaCO3) = 10/100 = 0.1 mol;
3) n (CO2) = n (CaCO3) = 0.1 mol;
4) V (CO2) = n (CO2) * Vm = 0.1 * 22.4 = 2.24 l.
Answer: The CO2 volume is 2.24 liters.



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