What is the volume of carbon dioxide generated by firing 500 g of CaCO3 limestone containing 20% impurities?
September 6, 2021 | education
| The decomposition reaction of limestone is described by the following chemical reaction equation:
CaCO3 = CaO + CO2;
When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.
Let’s calculate the available chemical amount of calcium carbonate substance.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 500 x 0.8 / 100 = 4 mol;
During the reaction, the same amount of carbon dioxide will be synthesized.
Let’s calculate its volume.
To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.
1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V CO2 = 4 x 22.4 = 89.6 liters;
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