What is the volume of carbon dioxide produced by combustion of 38 grams of ethylene?

univerkov | February 6, 2021 | education

1. Let’s write the reaction equation:

C2H4 + 3O2 = 2CO2 + 2H2O.

2. Find the amount of ethylene:

n (C2H4) = m (C2H4) / M (C2H4) = 38 g / 28 g / mol = 1.36 mol.

3. Using the reaction equation, we find the amount and then the volume of carbon dioxide (Vm is the molar volume, constant equal to 22.4 l / mol):

2n (CO2) = n (C2H4).

n (CO2) = n (C2H4) / 2 = 1.36 mol / 2 = 0.68 mol.

V (CO2) = n (CO2) * Vm = 0.68 mol * 22.4 l / mol = 15.2 l.

Answer: V (CO2) = 15.2 liters.

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