What is the volume of carbon dioxide produced by firing (t) 10g of limestone (calcium carbonate) containing 20% impurities?

The limestone decomposition reaction is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 10 x 0.8 / 100 = 0.08 mol;

During the reaction, the same amount of carbon dioxide will be synthesized.

Let’s calculate its volume.

To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.08 x 22.4 = 1.79 liters;