What is the volume of carbon dioxide produced by the decomposition of 6 moles of calcium carbonate?

Reaction equation: CaCO3 = CaO + CO2
According to the reaction equation, 1 mol of CaCO3 forms 1 mol of carbon dioxide, therefore n (CaCO3) = n (CO2) = 6 mol.
Let’s find the volume of gas by the formula: V = n * Vm, where Vm is the molar volume equal to 22.4 l / mol. V (CO2) = 6 mol * 22.4 L / mol = 134.4 L.
Answer: 134.4 liters of carbon dioxide are formed.

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