What is the volume of carbon dioxide released during the roasting of 50 g of limestone?

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

The decomposition of 1 mol of limestone synthesizes 1 mol of calcium oxide and 1 mol of carbon monoxide.

Find the chemical amount of calcium carbonate. For this purpose, we divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 50/100 = 0.5 mol;

Let us determine the volume of 0.5 mol of carbon dioxide.

To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V CO2 = 0.5 x 22.4 = 11.2 liters;