What is the volume of carbon dioxide released when 100 g of potassium carbonate interacts with 100 g of nitric acid

The reaction of dissolving sodium potassium in nitric acid is described by the following chemical reaction equation:

К2СО3 + 2НNO3 = 2КNO3 + CO2 + H2O;

When 1 mol of potassium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of nitric acid.

Let’s calculate the chemical amount of a substance containing 100 grams of potassium carbonate.

М К2СО3 = 39 x 2 + 12 + 16 x 3 = 138 grams / mol;

N K2CO3 = 100/138 = 0.725 mol;

Let’s calculate the chemical amount of a substance containing 100 grams of nitric acid.

M HNO3 = 1 + 14 + 16 x 3 = 63 grams / mol;

N HNO3 = 100/63 = 1.587 mol;

Thus, when 0.725 mol of soda is dissolved, 0.725 mol of carbon dioxide is synthesized. This will require 0.725 x 2 = 1.45 mol of acid.

Let’s calculate its volume. To do this, multiply the amount of substance and the standard volume of 1 mole of gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.725 x 22.4 = 16.24 liters;