What is the volume of carbon dioxide, which is formed during the combustion of 40 liters of ethane in oxygen?

Ethane combustion reaction:
2C2H6 + 7O2 = 4CO2 + 6H2O.
Etana was originally:
40 L: 22.4 L / mol = 1.786 mol.
Two times more carbon dioxide will be released, or:
1.786 * 2 * 22.4 = 80 liters.



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