What is the volume of carbon monoxide (5) formed during the decomposition of calcium carbonate

| May 17, 2021 | education

What is the volume of carbon monoxide (5) formed during the decomposition of calcium carbonate weighing 10.6 g? Calculate how many grams of salt will precipitate if this gas is passed through a calcium hydroxide solution.

The decomposition reaction of calcium carbonate when heated is described by the following chemical equation:

CaCO3 = CaO + CO2 ↑;

Let’s determine the chemical amount of calcium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 10.6 / 100 = 0.16 mol;

The same molar amount of carbon dioxide will theoretically be synthesized.

To calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V CO2 = 0.16 x 22.4 = 3.584 liters;

If this gas is passed through a solution of calcium hydroxide, then the reverse reaction will take place and an initial mass of calcium carbonate equal to 10.6 grams will be obtained.



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