What is the volume of carbon monoxide (IV) CO2 formed during the decomposition of 10.6 kg. calcium carbonate CaCo3.

The limestone decomposition reaction is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 10 600/100 = 106 mol;

During the reaction, the same amount of carbon dioxide and calcium oxide will be synthesized.

Let’s calculate its volume.

To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 106 x 22.4 = 2,374.4 liters = 2.3744 m3;