What is the volume of carbon monoxide (IV) formed when 16 g of methyl alcohol is burned?

Let’s write the solution in the following order:
1) Let’s make the equation: CH3 – OH + 2O2 = CO2 + 2H2O;
Combustion of methanol occurs with the formation of carbon dioxide and water.
2) Determine the number of moles of CH3OH if m (CH3OH) = 16 g;
Y (CH3OH) = 16/32 = 0.50 mol.
3) Let’s make a proportion based on the reaction equation:
0.50 mol (CH3OH) – x mol CO2;
hence, X mol (CO2) = 0.50 * 1/1 = 0.50 mol.
4) Let’s calculate the volume of CO2 according to Avogadro’s law: V (CO2) = 0.50 * 22.4 = 11.20 liters.
Answer: when methanol burns, carbon dioxide is released with a volume of 11.20 liters.