What is the volume of hydrogen and what mass of salt is obtained in the reaction of magnesium weighing

What is the volume of hydrogen and what mass of salt is obtained in the reaction of magnesium weighing 2.4 grams, with an excess of hydrochloric acid?

The reaction of magnesium with hydrochloric acid is described by the following chemical reaction equation.

Mg + 2HCl = MgCl2 + H2;

One mole of magnesium reacts with two moles of hydrochloric acid. This produces one mole of hydrogen. Let’s determine the amount of a substance contained in 2.4 grams of magnesium.

M Mg = 24 grams / mol;

N Mg = 2.4 / 24 = 0.1 mol;

0.1 mol of magnesium will react with 0.2 mol of hydrochloric acid. This forms 0.1 mol of hydrogen and 0.1 mol of magnesium chloride.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of hydrogen.

V H2 = 0.1 x 22.4 = 2.24 liters;

Let us determine the mass of 0.1 mol of magnesium chloride.

N MgCl2 = 0.1 mol;

M MgCl2 = 24 + 35.5 x 2 = 95 grams / mol;

m MgCl2 = 0.1 x 95 = 9.50 grams;