What is the volume of hydrogen at 6 grams under normal conditions?

m (H2) = 6 g.
Let’s determine the volume of hydrogen under normal conditions. We write down the solution.
First, we find the amount of substance. We use the following formula.
n = m / M.
M (H2) = 1 × 2 = 2 g / mol.
n = 6 g / 2 g / mol = 3 mol.
Then we find the volume of hydrogen. We use the following formula.
V = n × Vm = 3 mol × 22.4 L / mol = 67.2 L.
This means that the volume of 6 mol of hydrogen under normal conditions is 67.2 liters.
Answer: V (H2) = 67.2 liters.

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