What is the volume of hydrogen formed by the interaction of 6.5 g of zinc, with 50 g of 10% hydrochloric acid solution.

To dissolve zinc in acid, double the chemical amount of acid is required:

Zn + 2HCl → ZnCl2 + H2;

Determine the available quantities of reagents:

Let’s find the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 6.5 / 65 = 0.1 mol;

Let’s calculate the chemical amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 50 x 0.1 / 36.5 = 0.137 mol;

The acid is taken in deficiency.

0.5 mol of hydrogen is synthesized from 1 mole of acid.

We calculate the volume of 0.137 / 2 = 0.069 mol of hydrogen.

V H2 = 22.4 x 0.069 = 1.546 liters;