What is the volume of hydrogen formed by the interaction of zinc with 50 g of 12.5% sulfuric acid solution?

Given:
m solution (H2SO4) = 50 g
ω (H2SO4) = 12.5%

Find:
V (H2) -?

Solution:
1) Zn + H2SO4 => ZnSO4 + H2 ↑;
2) m (H2SO4) = ω (H2SO4) * m solution (H2SO4) / 100% = 12.5% * 50/100% = 6.25 g;
3) n (H2SO4) = m (H2SO4) / M (H2SO4) = 6.25 / 98 = 0.06 mol;
4) n (H2) = n (H2SO4) = 0.06 mol;
5) V (H2) = n (H2) * Vm = 0.06 * 22.4 = 1.3 liters.

Answer: The volume of H2 is 1.3 liters.