What is the volume of hydrogen formed by the reaction of 3.25 g of zinc with hydrochloric acid?

univerkov | March 5, 2021 | education

The equation for the reaction of zinc with hydrochloric acid:

Zn + 2HCl = ZnCl2 + H2

The amount of zinc substance:

v (Zn) = m (Zn) / M (Zn) = 3.25 / 65 = 0.05 (mol).

According to the reaction equation, 1 mole of H2 is formed per 1 mole of Zn, therefore:

v (H2) = v (Zn) = 0.05 (mol).

Thus, the volume of hydrogen evolved under normal conditions (n.a.):

V (H2) = v (H2) * Vm = 0.05 * 22.4 = 1.12 (l).

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