What is the volume of hydrogen formed when 325 g of zinc is dissolved in hydrochloric acid?

Metallic zinc “dissolves” in hydrochloric acid, the reaction is described by the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the molar amount of zinc. To do this, we divide its weight by the molar weight of elemental zinc.

M Zn = 65 grams / mol; N Zn = 325/65 = 5 mol;

The same amount of hydrogen will be released.

Let’s calculate its volume.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling the space of 22.4 liters).

V H2 = 5 x 22.4 = 112 liters;