What is the volume of hydrogen obtained by the interaction of hydrochloric acid weighing 7.3 g with zinc?

The interaction of zinc with hydrogen chloride occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

When 1 mole of metal dissolves, 1 mole of hydrogen gas is released. This requires 2 mol of hydrogen chloride.

Let’s calculate the amount of substance contained in 7.3 grams of hydrogen chloride.

To do this, we find the ratio of its weight to molar mass.

N HCl = 7.3 / (1 + 35.5) = 0.2 mol;

When reacting with 0.2 mol of hydrogen chloride, 0.1 mol of hydrogen gas is released.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.1 x 22.4 = 2.24 liters;

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