What is the volume of hydrogen released by the interaction of 0.1 mol of ethanol with an excess

What is the volume of hydrogen released by the interaction of 0.1 mol of ethanol with an excess of sodium. What kind of hydrogen is released?

Given:
n (C2H5OH) = 0.1 mol

Find:
V (H2) -?

1) Write the equation of a chemical reaction:
2C2H5OH + 2Na => C2H5ONa + H2 ↑;
2) Determine the amount of substance H2 (taking into account the coefficients in the reaction equation):
n (H2) = n (C2H5OH) / 2 = 0.1 / 2 = 0.05 mol;
3) Calculate the volume of H2 (under normal conditions):
V (H2) = n (H2) * Vm = 0.05 * 22.4 = 1.12 liters.

Answer: The volume of H2 is 1.12 liters.