What is the volume of hydrogen released by the interaction of 0.1 mol of ethanol with an excess of sodium. What kind of hydrogen is released?
n (C2H5OH) = 0.1 mol
V (H2) -?
1) Write the equation of a chemical reaction:
2C2H5OH + 2Na => C2H5ONa + H2 ↑;
2) Determine the amount of substance H2 (taking into account the coefficients in the reaction equation):
n (H2) = n (C2H5OH) / 2 = 0.1 / 2 = 0.05 mol;
3) Calculate the volume of H2 (under normal conditions):
V (H2) = n (H2) * Vm = 0.05 * 22.4 = 1.12 liters.
Answer: The volume of H2 is 1.12 liters.
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