What is the volume of hydrogen released during aromatization of 14.4 g of unbranched hexane.

The process of hexane aromatization occurs, we can confirm by writing down the reaction equation:
C6H14 = C6H6 + 4H2 – benzene and hydrogen are formed:
Let’s determine the molar masses of substances:
M (C6H14) = 12 * 6 + 1 * 14 = 86 g / mol;
M (H2) = 2 g / mol;
Let’s calculate the number of moles of hexane:
Y (C6H14) = m / M = 14.4 / 86 = 0.16 mol;
Let’s calculate the number of H2 moles based on the proportion:
0.16 mol (C6H14) – X mol (H2);
-1 mol -4 mol from here, X mol (H2) = 0.16 * 4/1 = 0.64 mol;
Let’s make calculations:
V (H2) = 0.64 * 22.4 = 14.3 liters.
Answer: when hexane is aromatized, hydrogen is released in a volume of 14.3 liters.