What is the volume of hydrogen released during the interaction of 130 grams of zinc with hydrochloric acid?

The interaction of zinc with hydrogen chloride occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

When 1 mole of metal dissolves, 1 mole of hydrogen gas is released.

Let’s calculate the amount of substance contained in a sample of 130 grams of metal.

To do this, we find the ratio of its weight to molar mass.

N Zn = 130/65 = 2 mol;

The same amount of hydrogen will be released during this interaction.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 2 x 22.4 = 44.8 liters;